13_Chapter 19 HomeworkCH19 Magnetism

13_Chapter 19 HomeworkCH19 Magnetism - Magnetism 19.26 153...

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Magnetism 153 19.26 The resistance of the loop is ( )( ) 8 3 42 1.70 10 m 8.00 m 1.36 10 1.00 10 m L R A ρ ×Ω == = × × and the current in the loop is 3 0.100 V 73.5 1.36 10 V I R A = sin NBIA The magnetic field exerts torque τ θ = on the loop, and this is a maximum when sin 1 = () ( ) . Thus, ( ) 2 T 73.5 A 2.00 m 118 N = max 1 0.400 m NBIA 19.27 The magnitude of the force a proton experiences as it moves perpendicularly to a magnetic field is ( ) ( ) sin sin 90.0 Fq v B e v B e v B + ° = This force is always directed perpendicular to the velocity of the proton and will supply
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