DirectCurrent Circuits
113
18.17
We name the currents
as shown.
Using Kirchhoff’s loop rule on the rightmost
loop gives
12
3
, , and
II
I
( )
()
3
2
5.00
1.00
I
I
−+
12.0 V 1.00+3.00
4.00 V
0
+
−
=
(
or
)
32
4.00 V
=
2.00
3.00
+
(
(1)
Applying the loop rule to the leftmost loop yields
) ( )
21
4.00 V+ 1.00
0
(
+5.00
8.00
+−
=
or
) ( )
2.00 V
=
4.00
3.00
−
123
+=
I
(2)
From Kirchhoff’s junction rule,
(3)
Solving equations (1), (2) and (3) simultaneously gives
3
=0.846 A,
1.31 A
I
=
=0.462 A, and
All currents are in the directions indicated by the arrows in the circuit diagram.
±²³³´
±
±
µ
µ¶²³
·
¸²³³
·
µ²³³
±
±
¶
±
±
¹²³³
±
µ²³³
±
º²³³
±
18.18
Observe that the center branch of this circuit, that is the branch containing points
a
and
b
, is not a continuous conducting path, so no current can flow in this branch. The only
This is the end of the preview.
Sign up
to
access the rest of the document.
 Spring '09
 Physics, Current, Work, The Circuit, 1.00 W, 8.00 W, 18.17 3.00 W

Click to edit the document details