15_Chapter 19 HomeworkCH19 Magnetism

15_Chapter 19 HomeworkCH19 Magnetism - Magnetism 19.32...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Magnetism 155 19.32 Since the centripetal acceleration is furnished by the magnetic force acting on the ions, 2 mv qvB r = or the radius of the path is mv r qB = . Thus, the distance between the impact points (that is, the difference in the diameters of the paths followed by the U and the isotopes) is 238 235 U () 238 235 238 235 5 27 19 2 2 23 .00 10 ms kg 238 u 235 u 1.66 10 u 1.60 10 C 0.600 T v drr mm qB ∆= = ×  =−  × ×  or 2 3.11 10 m 3.11 cm d × = 19.33 In the perfectly elastic, head-on collision between the -particle α and the initially stationary proton, conservation of momentum requires that mv 0 αα pp + = while conservation of kinetic energy also requires that ( ) o r v v 00 v 0 vv v = + . Using the fact that 4 p = and combining these equations gives ( ) 4 or p = 0 4 v ++ 3 5 v v = and ( ) 0 35 85 p vv vv =+ = Thus, 0 33 5 3 55 8 8 v v == = After the collision, each particle follows a circular path in the horizontal plane with the
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This document was uploaded on 10/20/2011.

Ask a homework question - tutors are online