15_Chapter 23 HomeworkCH23 Mirrors and Lenses

15_Chapter 23 HomeworkCH23 Mirrors and Lenses - Mirrors and...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Mirrors and Lenses 281 23.25 As parallel rays from the Sun ( ) object distance, p →∞ enter the transparent sphere from air ( ) 1 1.00 n = , the center of curvature of the surface is on the side the light is going toward (back side). Thus, R . It is observed that a real image is formed on the surface opposite the Sun, giving the image distance as 0 2 qR > = + . Then 12 nn 2 1 p += becomes 1.00 RR 0 2 2.00 which reduces to and gives 2 =− 2.00 n = 23.26 The wall of the aquarium is a plane ( ) R → ∞ refracting surface separating water and air . Thus, () 1 1.333 n = 2 1.00 n = 2 1 p gives the image position as 2 1 1.333 p n qp n    . When the object position changes by p , the change in the image position is 1.333 p q ∆= . The apparent speed of the fish is then given by
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.
Ask a homework question - tutors are online