156CHAPTER 19 19.35Treat the lightning bolt as a long, straight conductor. Then, the magnetic field is ()()()7450410TmA1.0010A2.0010T20.0 T22100 mIBrπµµππ−−×⋅×===×=19.36Model the tornado as a long, straight, vertical conductor and imagine grasping it with the right hand so the fingers point northward on the western side of the tornado. (that is, at the observatory’s location) The thumb is directed downward, meaning that the conventional current is downward or negative charge flows upward. The magnitude of the current is found from 02rBIµπ=as ()()38-7029.0010m1.5010T2675 A410T m ArBIππµπ−××===×⋅19.37From 02BIrµπ=, the required distance is ()()()-7303410TmA20 A2.410m2.4 mm221.710TIrBπµππ−−×⋅===×=×19.38Assume that the wire on the right is wire 1 and that on the left is wire 2. Also, choose the
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