248CHAPTER 22 22.29Using Snell’s law gives ( )111.000 sin83.00sinsinsin48.221.331airiredrednnθ−−°===°and ( )1.000 sin83.00sinsinsin47.791.340airibluebluenn°=°22.30The angles of refraction for the two wavelengths are ( )1.00 0 sin30.00sinsinsin18.041.615airiredrednn°=°and ( )1.00 0 sin30.00sinsinsin17.641.650airibluebluenn°=°Thus, the angle between the two refracted rays is 18.0417.640.40redblueθθ∆=−=°−°=°22.31(a) The angle of incidence at the first surface is 1i30=°, and the angle of refraction is 11isinnairglassnn1rsi=−11.0sin30n191.5−°1r9071si°Also, α− =°and 1806049β=°−=°Therefore, the angle of incidence at the second surface is 2i9041==°. The
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