16_Chapter 22 HomeworkCH22 Reflection and Refraction of Light

16_Chapter 22 HomeworkCH22 Reflection and Refraction of Light

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248 CHAPTER 22 22.29 Using Snell’s law gives ( ) 11 1.000 sin83.00 sin sin sin 48.22 1.331 air i red red n n θ −−  ° == =   ° and ( ) 1.000 sin83.00 sin sin sin 47.79 1.340 air i blue blue n n ° = ° 22.30 The angles of refraction for the two wavelengths are ( ) 1.00 0 sin30.00 sin sin sin 18.04 1.615 air i red red n n ° = ° and ( ) 1.00 0 sin30.00 sin sin sin 17.64 1.650 air i blue blue n n ° = ° Thus, the angle between the two refracted rays is 18.04 17.64 0.40 red blue θθ ∆= = ° ° = ° 22.31 (a) The angle of incidence at the first surface is 1i 30 , and the angle of refraction is 1 1i sin n air glass n n 1r si = 1 1.0sin30 n 19 1.5 ° 1r 90 71 si ° Also, α − =° and 180 60 49 β = °− = ° Therefore, the angle of incidence at the second surface is 2i 90 41 = = ° . The
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This document was uploaded on 10/20/2011.

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