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17_Chapter 15 HomeworkCH15 Electric Forces and Electric Fields

# 17_Chapter 15 HomeworkCH15 Electric Forces and Electric Fields

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Electric Forces and Electric Fields 17 Thus, 3 2 3 1.87 10 N C x E E E + = × Σ = and 1 144 N C y E E Σ = − = − giving ( ) ( ) 2 2 3 1.88 10 N C R x y E E E = Σ + Σ = × and ( ) ( ) 1 1 tan tan 0.0769 y x E E θ = Σ Σ = 4.40 = − ° Hence 3 1.88 10 N C at 4.40° below the + ax R x = × E JG is 15.25 From the symmetry of the charge distribution, students should recognize that the resultant electric field at the center is 0 R = E
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