17_Chapter 18 HomeworkCH18 Direct-Current Circuits

# 17_Chapter 18 HomeworkCH18 Direct-Current Circuits - 115...

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Direct-Current Circuits 115 18.21 First simplify the circuit by combining the series resistors. Then, apply Kirchhoff’s junction rule at point a to find Next, we apply Kirchhoff’s loop rule to the rightmost loop to obtain 1 2 2.00 A I I + = ( ) ( ) 1 2 12.0 0 I I ( ) 8.00 V 6.00 + ( ) = or ( ) 1 12.0 2.00 I 1 I = 8.00 V 6.00 + ( A 0 This yields Finally, apply Kirchhoff’s loop rule to the leftmost loop to obtain 1 1.78 A I = )( ) ( ) 1 1 0 A 6.00 I 4.00 2.0 8.00 V 0 ε + ( )( ) ( )( + = ) or 1 4.00 2.00 ε A 6.00 1.78 = + A 8.00 V 10.7 V = 18.22 From Kirchhoff’s point rule, note that 1 I I I 2 = in the circuit shown at the right. Going counterclockwise around the upper pane of the circuit, Kirchhoff’s loop rule gives
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