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Mirrors and Lenses
283
(b) If
f
=−
, then
12.0 cm
()
1
11
2
.
0
c
p
M
−
m
1.00
M
⇒
24.0 cm
p
( )
1.00
=+
⇒
0
object is against the lens
Mp
=
Note that in both cases,
M
approaches +1.00 only in the limit as
p
approaches zero.
Note also in part (b), the object must be virtual to obtain
1.00
M
= −
.
23.31
From the thin lens equation,
111
p
qf
+
=
, the image distance is found to be
( )
( )
20.0 cm
20.0 cm
20.0 cm
20.0 cm
p
p
fp
q
pf p
p
−
==
=
−
−−
−
+
(a) If
40.0
p
=
, then
and
cm
13.3 cm
q
( )
13.3 cm
13
40.0 cm
q
M
p
−
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This document was uploaded on 10/20/2011.
 Spring '09
 Physics, Work

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