158CHAPTER 19 (b) At point P, ()10.200 m2r=and Bis directed at 11135θ=+°. The magnitude of is 1B( )701110TmA.00A2.12 T220.2002IBrπµ413m−×⋅===The contribution from wire 2 is in the –xdirection and has magnitude ( )( )7220Tm00A5.00 T2200mIBr5.20ππ−=cos135cos1802.12 T c1355.00 T cos1806.xBBBTherefore, the components of the net field at point Pare: 12os50 Tµµ°=−=°+°+and ( )s35sin2.12 T syBin1180in13501.50 T+=+=°Therefore, 6.67 TnetxyB=+=at 116.50 Ttan1.50 TxyBB−−tan77.0=°or 6.67 T at 77.0 to the left of vertnetBJGical ±±±²±³²²²³²±³±²±²±´µ¶³±·¸·¹º»¼½·±¾³´·¸·²»¼½·±¾²19.41Call the wire along the xaxis wire 1 and the other wire 2. Also, choose the positive
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