192CHAPTER 20 20.47()2231170.010H2.00 A0.140 J22LPELI−== ×=20.48(a) The inductance of a solenoid is given by 20LNAµ=l, where Nis the number of turns on the solenoid, Ais its cross-sectional area, and is its length. For the given solenoid, l( )( )( )227203410T m A3005.001m4.4410H0.200 mNrLµππ−×⋅===×l0−−×(b) When the solenoid described above carries a current of 0.500 AI=, the stored energy is 24.4410H0.500 A5.5510LPELI×=×4J 20.49The current in the circuit at time tis (1tIeR)τε−=−, and the energy stored in the inductor is 212LLI=PE(a) As t, →∞max24 V3.0 A8.0 IIR→===Ω, and 22max
This is the end of the preview. Sign up
access the rest of the document.