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18_Chapter 23 HomeworkCH23 Mirrors and Lenses

# 18_Chapter 23 HomeworkCH23 Mirrors and Lenses - 284 CHAPTER...

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284 CHAPTER 23 23.32 Comparing the given equation to the thin lens equation, 1 1 1 p q f + = , we see that the lens is a convergent lens ( ) 0 f > with focal length 7.50 cm f = . Also, the image distance is negative ( ) 3.50 q = − p , meaning the image is virtual. The lateral magnification is 3.50 q p p p = + 3.50 M = − = − so the image is upright and enlarged. (a) Using the information deduced above, the thin lens equation becomes 1 1 1 3.50 7.50 cm p p = giving ( ) 1 7.50 cm 1 5.36 cm 3.50 = = + p (b) The image distance is then ( ) 3.50 5.36 cm 18.8 cm q = − = − (c) See the ray diagram at the right. (d) A simple magnifier is a device that uses a convergent lens to form an upright, enlarged, virtual image of a real
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