This preview shows page 1. Sign up to view the full content.
284
CHAPTER 23
23.32
Comparing the given equation to the thin lens equation,
111
p
qf
+
=
, we see that the lens
is a convergent lens
( )
0
f
>
with focal length
7.50 cm
f
=
. Also, the image distance is
negative
( )
3.50
q
=−
p
, meaning the image is virtual. The lateral magnification is
3.50
qp
pp
−
=+
3.50
M
so the image is upright and enlarged.
(a) Using the information deduced above, the thin lens equation becomes
11
1
3.50
7.50 cm
−=
giving
()
1
7.50 cm
1
5.36 cm
3.50
=
+
p
(b) The image distance is then
3.50 5.36 cm
18.8 cm
q
= −
(c) See the ray diagram at the right.
±
²³
(d) A simple magnifier is a device that uses a convergent
lens to form an upright, enlarged, virtual image of a real
object. One possible problem whose solution would
This is the end of the preview. Sign up
to
access the rest of the document.
This document was uploaded on 10/20/2011.
 Spring '09
 Physics, Work

Click to edit the document details