19_Chapter 22 HomeworkCH22 Reflection and Refraction of Light

# 19_Chapter 22 HomeworkCH22 Reflection and Refraction of Light

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Reflection and Refraction of Light 251 22.38 The critical angle for this material in air is 11 1.00 sin sin 47.3 1.36 air c pipe n n θ −−  ===   90.0 42.7 rc ° Thus, and from Snell’s law, ( ) 1.36 sin42.7 sin 67.2 1.00 ° == sin sin pipe r i air n n = ° 22.39 The light must be totally reflecting from the surface of a hot air layer just above the road surface. The angle of reflection, and hence the critical angle, is 90.0 1.20 88.8 c = °− °= ° . Thus, from 2 1 sin c n n = ( , we find ) 21 sin 1.000 3 sin88.8 1.000 08 c nn ° = 22.40 The circular raft must cover the area of the surface through which light from the diamond could emerge. Thus, it must form the base of a cone (with apex at the
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## This document was uploaded on 10/20/2011.

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