88CHAPTER 17 Thus, ()28any combination of length and diameter satisfying the relation 4.810md−=×l1.0 m=lwill be suitable. A typical combination might be and 8244.810m2.210m0.22 mmd−−=×=Yes3cm() ( ), such heating elements could easily be made from less than 0.5of Nichrome. The volume of material required for the typical wire given above is 6322473310 cm2.210m1.0 m1.510m0.15 cm1 mVAdππ===×= ×=ll317.47 The energy that must be added to the water is 6J1kWh200 kg4 186 80 C15 C15 kWhkgC3.6010 JEmcT=∆=°−°=⋅°×and the cost is ( )15 kWh$0.080 kWh$1.2tE rate
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