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118
CHAPTER 18
18.26
Using Kirchhoff’s loop rule on the outer
perimeter of the circuit gives
( ) ( )
13
12 V
0.01
0.06
0
II
+−
−
=
3
6
1.2
10 A
+=×
or
(1)
For the rightmost loop, the loop rule gives
( ) ( )
23
10 V
1.00
0.06
0
++
−
=
0.06
10 A
−=
−
123
III
=+
or
(2)
Applying Kirchhoff’s junction rule at either junction gives
(3)
Solving equations (1), (2), and (3) simultaneously yields
( )
2
and
1.7
10 A (in starter)
==
×
0.28 A in dead battery
18.27
Assume currents
in the directions shown.
Then, using Kirchhoff’s junction rule at junction
a
gives
(1)
Applying Kirchhoff’s loop rule on the upper loop,
12
3
, , and
I
2
I
(
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 Spring '09
 Physics, Current, Work

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