160CHAPTER 19 (d) The cable creates zero field at exterior points, since a loop in Ampère’s law encloses zero total current. 19.44(a) ( )( )()270124410TmA10.0A220.100m2.0010N m attractionIIFLdπµππ−−×⋅===×(b) The magnitude remains the same as calculated in (a), but the wires are repelled. Thus, 42.0010N m repulsionFL−19.45In order for the system to be in equilibrium, the repulsive magnetic force per unit length on the top wire must equal the weight per unit length of this wire. Thus,0.080 N m2F, and the distance between the wires will be ( )( )( )73410T m A60.0 A30.0 A20.080 N m20.080 N m4.510m4.5 mmd−−=19.46The magnetic forces exerted on the top and bottom segments of the rectangular loop are
This is the end of the preview. Sign up
access the rest of the document.