20_Chapter 19 HomeworkCH19 Magnetism

# 20_Chapter 19 HomeworkCH19 Magnetism - 160 CHAPTER 19 (d)...

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160 CHAPTER 19 (d) The cable creates zero field at exterior points, since a loop in Ampère’s law encloses zero total current. 19.44 (a) ( )( ) () 2 7 012 4 41 0 T m A 1 0 . 0 A 22 0 . 1 0 0 m 2.00 10 N m attraction II F Ld π µ ππ ×⋅ == (b) The magnitude remains the same as calculated in (a), but the wires are repelled. Thus, 4 2.00 10 N m repulsion F L 19.45 In order for the system to be in equilibrium, the repulsive magnetic force per unit length on the top wire must equal the weight per unit length of this wire. Thus, 0.080 N m 2 F , and the distance between the wires will be ( )( )( ) 7 3 4 10 T m A 60.0 A 30.0 A 2 0.080 N m 2 0.080 N m 4.5 10 m 4.5 mm d = 19.46 The magnetic forces exerted on the top and bottom segments of the rectangular loop are
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## This document was uploaded on 10/20/2011.

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