This preview shows page 1. Sign up to view the full content.
286
CHAPTER 23
23.36
We are given that
. Then, the thin lens equation,
12.5 cm and
30.0 cm
fq
=+
=−
111
p
qf
+=
, gives
( )( )
30.0 cm
12.5 cm
8.82 cm
30.0 cm
12.5 cm
−
=
+
−−
−
p
==
and the lateral magnification is
30.0 cm
3.40
8.82 cm
q
M
p
−
= +
Since
0
M
>
, the image is
upright
23.37
All virtual images formed by diverging lenses are upright images. Thus,
0
M
>
, and the
magnification gives
1
3
q
M
p
, or
3
p
q
Then, from the thin lens equation,
13 21
p
pp
f
−
=
or
22
p
ff
=
The object should be placed at distance
2
in front of the lens
f
23.38
(a) The total distance from the object to the real image is the objecttoscreen distance,
This is the end of the preview. Sign up
to
access the rest of the document.
This document was uploaded on 10/20/2011.
 Spring '09
 Physics, Work

Click to edit the document details