20_Chapter 23 HomeworkCH23 Mirrors and Lenses

20_Chapter 23 HomeworkCH23 Mirrors and Lenses - 286 CHAPTER...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
286 CHAPTER 23 23.36 We are given that . Then, the thin lens equation, 12.5 cm and 30.0 cm fq =+ =− 111 p qf += , gives ( )( ) 30.0 cm 12.5 cm 8.82 cm 30.0 cm 12.5 cm = + −− p == and the lateral magnification is 30.0 cm 3.40 8.82 cm q M p = + Since 0 M > , the image is upright 23.37 All virtual images formed by diverging lenses are upright images. Thus, 0 M > , and the magnification gives 1 3 q M p , or 3 p q Then, from the thin lens equation, 13 21 p pp f = or 22 p ff = The object should be placed at distance 2 in front of the lens f 23.38 (a) The total distance from the object to the real image is the object-to-screen distance,
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This document was uploaded on 10/20/2011.

Ask a homework question - tutors are online