286CHAPTER 23 23.36We are given that . Then, the thin lens equation, 12.5 cm and 30.0 cmfq= += −111pqf+=, gives ()()30.0 cm12.5 cm8.82 cm30.0 cm12.5 cm−= +−−−q fpqf==and the lateral magnification is 30.0 cm3.408.82 cmqMp−= −= −= +Since 0M>, the image is upright 23.37All virtual images formed by diverging lenses are upright images. Thus, 0M>, and the magnification gives 13qMp= −= +, or 3pq=−Then, from the thin lens equation, 1321pppf−=−=or 22pff=−=The object should be placed at distance 2in front of the lens
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