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20_Chapter 23 HomeworkCH23 Mirrors and Lenses

20_Chapter 23 HomeworkCH23 Mirrors and Lenses - 286 CHAPTER...

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286 CHAPTER 23 23.36 We are given that . Then, the thin lens equation, 12.5 cm and 30.0 cm f q = + = − 1 1 1 p q f + = , gives ( )( ) 30.0 cm 12.5 cm 8.82 cm 30.0 cm 12.5 cm = + q f p q f = = and the lateral magnification is 30.0 cm 3.40 8.82 cm q M p = − = − = + Since 0 M > , the image is upright 23.37 All virtual images formed by diverging lenses are upright images. Thus, 0 M > , and the magnification gives 1 3 q M p = − = + , or 3 p q =− Then, from the thin lens equation, 1 3 2 1 p p p f =− = or 2 2 p f f =− = The object should be placed at distance 2 in front of the lens
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