286CHAPTER 23 23.36We are given that . Then, the thin lens equation, 12.5 cm and 30.0 cmfq=+=−111pqf+=, gives ( )( )30.0 cm12.5 cm8.82 cm30.0 cm12.5 cm−=+−−−p==and the lateral magnification is 30.0 cm3.408.82 cmqMp−= +Since 0M>, the image is upright 23.37All virtual images formed by diverging lenses are upright images. Thus, 0M>, and the magnification gives 13qMp, or 3pqThen, from the thin lens equation, 13 21pppf−=or 22pff=The object should be placed at distance 2in front of the lensf23.38(a) The total distance from the object to the real image is the object-to-screen distance,
This is the end of the preview. Sign up
access the rest of the document.