Mirrors and Lenses287(b) If 4.00p=, then and m1.00 mq=1.00 m14.00 m4qMp=−=−=−In this case, the image is real, in4.00 mq=verted, and one-quarter the size of the object If , then and 1.00 mp=4.00 m41.00 mqMp=−=−. In this case, the image is real, inverted, mes thand four tie size of the object 23.39Since the light rays incident to the first lens are parallel, 1p=∞and the thin lens equation gives . The virtual image formed by the first lens serves as the object for the second lens, so 1110.0 cmqf==−230.0 cmp=+2q=∞140.0 cmq=. If the light rays leaving the second lens are parallel, then and the thin lens equation gives 2240.0 cfpm . 23.40With pand , the thin lens equation gives the position of the image formed by the first lens as 120.0 cm=125.0 cmf
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