22_Chapter 16 HomeworkCH16 Electrical Energy and Capacitance

22_Chapter 16 HomeworkCH16 Electrical Energy and...

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56 CHAPTER 16 16.40 The original circuit reduces to a single equivalent capacitor in the steps shown below. ± ² ³ ± ³ ± ³ ´ ³ ´ ³ ² ³ µ ± ³ µ ³ ± ² ³ ¶· ± ² ± ² ³ ± ³ ± ³ ³ ³ ² ³ ³ ³ ± ³ ± 1 1 12 11 1 1 3.33 F 5.00 F 10.0 F s C CC µ µµ  =+ = + =   ( ) 13 2 3.33 F 2.00 F 8.66 F ps s CCCC =++= + = ( ) 222 2 10.0 F 20.0 F p CCC =+= = 1 1 1 1 6.04 F 8.66 F 20.0 F eq pp C = + = 16.41 Refer to the solution of Problem 16.40 given above. The total charge stored between points a and b is ( ) ( )( ) 6.04 F 60.0 V 362 C eq eq ab QC V =∆= = 362 C ppe q QQQ Then, looking at the third figure, observe that the charges of the series capacitors of that
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This document was uploaded on 10/20/2011.

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