22_Chapter 19 HomeworkCH19 Magnetism

# 22_Chapter 19 HomeworkCH19 Magnetism - perpendicular to the...

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162 CHAPTER 19 The forces acting on the sides of the loop lie in the plane of the loop, are perpendicular to the sides, and are directed away from the interior of the loop. Thus, they tend to stretch the loop but do not tend to rotate it. The torque acting on the loop is 0 τ = 19.50 (a) The magnetic force supplies the centripetal acceleration, so 2 B mv r = qv . The magnetic field inside the solenoid is then found to be ( ) ( ) () ( ) 31 4 6 19 2 9.11 10 kg 1.0 10 m s 2.847 10 T 2.8 T 1.60 10 C 2.0 10 m mv B qr µ −− ×× == = × = ×× (b) From B 0 n I µ , the current is the solenoid is found to be () () () 6 -7 0 4 2.847 10 T 41 0 T m A2 5 t u r n s c m 0 0 c m 1 m 9.1 10 A 0.91 mA B I n µ π
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Unformatted text preview: perpendicular to the plane of the coil makes an angle of 90 35 55 = = with the magnetic field. Thus, the torque exerted on the loop is ( )( )( ) ( ) 2 sin 1 0.30 T 25 A 0.30 m si NBIA = = n55 1.7 N m = 19.52 Since the magnetic force must supply the centripetal acceleration, 2 qvB mv r = or the radius of the path is r mv qB = . (a) The time for the electron to travel the semicircular path (of length r ) is ( ) ( )( ) 31 19 9 9.11 10 kg 1.60 10 C 0.010 0 T 1.79 10 s 1.79 ns r mv m t v v qB qB = = = = = =...
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## This document was uploaded on 10/20/2011.

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