288CHAPTER 23 23.41The thin lens equation gives the image position for the first lens as ()( )11130.0 cm15.0 cm30.0 cm30.0 cm15.0 cmpfq===+−−and the magnification by this lens is 11130.0 cm1.0030.0 cmqMp=−The real image formed by the first lens serves as the object for the second lens, so . Then, the thin lens equation gives 2140.0 cm10.0 cmpq=+( )( )22210.0 cm15.0 cm30.0 cm10.0 cm15.0 cmq=−and the magnification by the second lens is ( )22230.0 cm3.0010.0 cmqMp−=+Thus, the final, virtual image is located 30.0 cm in front of the second lens and the overall magnification is ( )( )121.003.003.00M−+=−MM23.42(a) With p, the thin lens equation gives the position of the image formed
This is the end of the preview. Sign up
access the rest of the document.