Electrical Energy and Capacitance5716.42Recognize that the 7.00 F and the 5.00 Fµof the center branch are connected in series. The total capacitance of that branch is 1112.92 F7.005.00sC−=4.00 =+Then recognize that this capacitor, the Fcapacitor, and the 6.00 Fcapacitor are all connected in parallel between points aand b. Thus, the equivalent capacitance between points aand bis 4.00eqCF2.92 F+6.00 F12.9 Fµµ=±²³³±´±²µ²³³±´¶²³³±´·²³³±´16.43The capacitance is ( )( )122242130-38.8510CN m2.0010m3.5410F5.0010 mACd−−−×⋅×∈===××and the stored energy is ()2213113.5410F12.0 V2.55
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