23_Chapter 16 HomeworkCH17 Current and Resistance

23_Chapter 16 HomeworkCH17 Current and Resistance - Current...

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Current and Resistance 91 17.53 (a) The total power you now use while cooking breakfast is ( ) 1200 500 W 1.70 kW =+ = P () ( ) The cost to use this power for 0.500 h each day for 30.0 days is () h 00 30.0 days $0.120 kWh $3.06 day cost   =     1.70 kW 0.5 t rate ∆× = P (b) If you upgraded, the new power requirement would be: ( ) 2 400 500 W=2 900 W P and the required current would be 2 900 W 26.4 A 20 A 110 V I V == = > P No , your present circuit breaker cannot handle the upgrade. 17.54 (a) The charge passing through the conductor in the interval is represented by the area under the
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This document was uploaded on 10/20/2011.

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