24_Chapter 18 HomeworkCH18 Direct-Current Circuits

24_Chapter 18 HomeworkCH18 Direct-Current Circuits - 122...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
122 CHAPTER 18 18.35 From ( ) max 1 t e QQ τ =− , we have at 0.900 s t = , 0.900 s max Q e Q 10 = . 6 0 0 Thus, 0.900 s 0.400 e = , or () ln 0.400 0.900 s −= giving the time constant as 0. 982 s ln 900 s 0. 0.400 = 18.36 (a) max R I ε = , so the resistance is 4 -3 max 48.0 V 9.60 10 0.500 10 A R I == × RC The time constant is = , so the capacitance is found to be 5 4 0.960 s 10 F 10.0 F 9.60 10 C R 1.00 µ × = = ×Ω (b) ( )( ) max 10.0 F 48.0 V 480 C QC = 1.92 s t = , so the charge stored in the capacitor at is 1.92 s 2 0.960 s max 1 480 C 1 480 C 1 415 C t e e e µµ  = − = =   18.37 (a) The current drawn by each appliance is
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.
Ask a homework question - tutors are online