360
CHAPTER 25
25.54
(a) The image distance for the objective lens is
()
( )
2
2
11
1
2
40.0 m
8.00
10 m
8.02
10
m
8.02 cm
40.0 m
8.00
10 m
pf
q
−
×
==
=
×=
−−
×
The magnification by the objective is
1
Mh
h q
p
′
=
=−
, so the size of the image
formed by this lens is
2
1
1
1
8.02
10
m
30.0 cm
0.060 1 cm
40.0 m
q
hhM h
p
−
×
′
== =
=
(b) To have parallel rays emerge from the eyepiece, its virtual object must be at its focal
point, or
2.00 cm
ee
−
(c) The distance between the lenses is
1
8.02 cm
2.00 cm
6.02 cm
e
Lq p
=+=
−
=
(d) The overall angular magnification is
1
8.00 cm
4.00
e
f
m
f
=
−
25.55
The angular magnification is
o
m
θθ
=
, where
θ
is the angle subtended by the final
image, and
o
is the angle subtended by the object as shown in the figure. When the
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 Spring '09
 Physics, Work, angular magnification

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