26_Chapter 16 HomeworkCH17 Current and Resistance

# 26_Chapter 16 HomeworkCH17 Current and Resistance - 94...

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94 CHAPTER 17 (c) The filament is tightly coiled to fit the required length into a small space (d) From ( ) 0 0 1 T T α = + L L , where ( ) 1 6 4.5 10 C α = × ° , the length at is 0 20 C T = ° ( ) ( ) ( ) ( ) 0 0 25 m 1 1 4.5 10 C L L T T α = = = + + × ° 1 6 26 m C 2 600 C 20 ° ° 17.60 Each speaker has a resistance of 4.00 R = and can handle 60.0 W of power. From , the maximum safe current is 2 I R = P max 60.0 W 4.00 R = = 3.87 A = I Thus, the system is not adequately protected by a 4.00 A fuse. 17.61 The cross-sectional area of the conducting material is ( ) 2 2 outer inner A r r π = Thus, ( )( ) ( ) ( ) 5 2 2 2 2 2 3.5 10 m 4.0 10 m 1.2 10 m 0.50 10 m L R A ρ π × Ω⋅ × = = × × 7 3.7 10 37 M
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