292CHAPTER 23 23.47Since q=+when , we find that 8.00 cm10.0 cmp111fpq=+=20.0p=118.010.0 cm80.0 cmcm18.00 cm+=Then, when , 111qfp18.080.0 c1m20.0 cm18.04.0014.080.0 cm80.0 cm−=−=−==or 80.0 cm14.0==5.71 cm+qThus, a real image is formed 5.71 cm in front of the mirror 23.48Applying the thin lens equation to the first lens gives ( )( )()11112 cm6.0 cm4.0 cm12 cm6.0 cmpfq−=−−−−The virtual image formed by the first lens serves as the object for the second lens. If the image formed by that converging lens is to be located at infinity, the image formed by the diverging lens must be located at the focal point in front of the converging lens.
This is the end of the preview. Sign up
access the rest of the document.