27_Chapter 17 HomeworkCH17 Current and Resistance

# 27_Chapter 17 HomeworkCH17 Current and Resistance - Current...

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Current and Resistance 95 17.63 The power the beam delivers to the target is ( ) ( )( ) 6 3 4.0 10 V 25 10 A 1.0 10 W V I = ∆ = × × = × P 5 The mass of cooling water that must flow through the tube each second if the rise in the water temperature is not to exceed 50°C is found from ( ) ( m t c T ) = ∆ P as ( ) ( ) ( ) 5 1.0 10 J s 0.48 kg s 4 186 J kg C 50 C m t c T × = = = ⋅° ° 17.64 The volume of the material is 3 6 3 3 6 3 50.0 g 1 m 6.36 10 m 7.86 g cm 10 cm mass V density = = = × L = Since V A , the cross-sectional area of the wire is A V L = (a) From 2 L L L R A V L V ρ ρ ρ = = = , the length of the wire is given by ( ) ( ) 6 3 -8 1.5 6.36 10 m 9.3 m 11 10 m R V L ρ ×
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