27_Chapter 17 HomeworkCH17 Current and Resistance

27_Chapter 17 HomeworkCH17 Current and Resistance - Current...

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Current and Resistance 95 17.63 The power the beam delivers to the target is () ( )( ) 63 4.0 10 V 25 10 A 1.0 10 W VI =∆ = × × = × P 5 The mass of cooling water that must flow through the tube each second if the rise in the water temperature is not to exceed 50°C is found from ( ) ( mt cT ) = ∆∆ ∆ P as 5 1.0 10 J s 0.48 kg s 4 186 J kg C 50 C m tcT × == = ∆∆ °° 17.64 The volume of the material is 3 363 50.0 g 1 m 6.36 10 m 7.86 g cm 10 cm mass V density  = ×   L =⋅ Since VA , the cross-sectional area of the wire is A VL = (a) From 2 LLL R A VL V ρ ρρ = , the length of the wire is given by -8 1.5 6.36 10 m 9.3 m 11 10 m RV L
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This document was uploaded on 10/20/2011.

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