{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

27_Chapter 22 HomeworkCH22 Reflection and Refraction of Light

27_Chapter 22 HomeworkCH22 Reflection and Refraction of Light

This preview shows page 1. Sign up to view the full content.

Reflection and Refraction of Light 259 22.54 From the sketch at the right, observe that the angle of incidence at A is the same as the prism angle at point O . Given that 60.0 θ , application of Snell’s law at point A gives ( ) 1.50sin 1.00 sin60.0 β 35.3 or = ° From triangle AOB , we calculate the angle of incidence and reflection, γ , at point B : ( ) ( ) 90.0 90.0 180 + ° = ° or 60.0 35.3 24.7 θβ = −= ° ° = ° Now, we find the angle of incidence at point C using triangle BCQ : ( ) ( ) ( ) 90.0 90.0 90.0 180 δθ °− + ° ( + = ° or ) 90.0 90.0 84.7 5.26 δ θγ + = ° ° − =° Finally, application of Snell’s law at point C gives ( ) ( ) ( ) 1.00 sin 1.50 sin 5.26 φ = ° or () 1 sin 1.50sin5. 26 = 7.91 ° ± ²³ ´ µ ± ± ² ³³ ´ µ 9±²±³´µ´ ± 22.55 The path of a light ray during a reflection and/or refraction process is always
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

Ask a homework question - tutors are online