Mirrors and Lenses29323.50Since the object is midway between the lens and mirror, the object distance for the mirror is . The mirror equation gives the image position as 112.5 cmp=+1112120qRp21541.0 cm12.5 cm50.0 cm50.0 cm−=− =−==225.0 cmp, or This image serves as the object for the lens, so 150.0 cmq125.0 cmq=−=−. Note that since , this is a virtual object. The thin lens equation gives the image position for the lens as 20<p( )( )()2225.0 cm16.7 cm25.0 cm16.7 cmpf−−==−−2q20q<50.3 cm=−Since , this is a virtual image that is located 50.3 cm in front of the lens or 25.3hind thecm bemirror . The overall magnification is ( )1250.3 cm50.0 cm12.5 cm25.0 cmMMM−== −=−−−+8.05=qqpp−Since 0M>, the final image is upright 23.51As light passes left-to-right through the lens, the image position is given by
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