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27_Chapter 24 HomeworkCH24 Wave Optics

# 27_Chapter 24 HomeworkCH24 Wave Optics - Wave Optics 24.58...

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Wave Optics 329 24.58 The wavelength is 340 m s 0.170 m 2 000 Hz sound v f λ = = = sin d m Maxima occur where θ λ = , or ( ) 1 sin m d θ λ = for 0, 1, 2, m = Since , 0.350 m d = 0.486 d λ = which gives ( ) 1 sin 0.486 m θ = For , this yields 0,1, and 2 = m max 3 m ima at 0 , 29.1 , and 76. ° ° sin 3 ° 1 No solutions exist for since that would imply θ > Minima occur where ( ) sin d m 1 2 θ λ = + or ( ) 1 sin 2 m 1 2 d λ θ + = = for m With 0, 1, 2, 0.486 d λ = , this becomes ( )( ) 1 0.243 m = + 1 sin 2 θ For , we find 0 and 1 = m minima 2 m at 14.1 and 46.8 ° ° sin 1 No solutions exist for since that would imply θ > 24.59 The source and its image, located 1.00 cm below the mirror, act as a pair of coherent sources. This situation may be treated as double-slit interference, with the slits separated
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