228
CHAPTER 21
21.60
L
XL
ω
=
, so
L
=
Then,
()
11
C
L
X
CCXL
==
which gives
( )
8.0
C
Ω Ω
12
LC
LXXC
=⋅
=
or
( )
2
96
L
=Ω
C
(1)
From
00
1
2
f
LC
ωπ
, we obtain
2
0
1
2
LC
f
π
=
Substituting from Equation (1), this becomes
22
96
C
2
0
1
2
f
Ω=
or
5
2.6
10
F
26 F
6
2
2
0
0
0
H
z
9
6
0
29
C
f
µ
ππ
−
=
×
=
ΩΩ
Then, from Equation (1),
( )( )
25
3
10
F
2.5
10
H
2.5 mH
−−
×
=×
=
96
2.6
L
21.61
(a) The box cannot contain a capacitor since a steady DC current cannot flow in a series
circuit containing a capacitor. Since the AC and DC currents are different, even
when a 3.0 V potential difference is used in both cases, the box must contain a
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 Spring '09
 Physics, Current, Work, Alternating Current, Direct Current, Potential difference, reactive element, DC Currents, steady dc

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