Reflection and Refraction of Light
261
22.57
Refer to the figure given at the right.
(
)
(
)
1
2
4
3
min
δ
α
ε
θ
θ
θ
θ
=
+
=
−
+
−
abc
bcd
Note that triangles
and
are
congruent. Therefore,
β
γ
=
2
3
and their
complementary angles are also equal,
or
θ
θ
1
sin
n
=
.
From Snell’s law at point
a
,
2
sin
θ
θ
=
(1)
and at point
d
,
4
3
sin
sin
n
θ
θ
=
Since
2
3
θ
θ
=
, comparison of these results shows that
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 Spring '09
 Physics, Work, Light, Reflection And Refraction, Snell's Law, Sin

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