33_Chapter 22 HomeworkCH22 Reflection and Refraction of Light

33_Chapter 22 HomeworkCH22 Reflection and Refraction of Light

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Reflection and Refraction of Light 265 (b) Observe from the figure above that sin Ld φ = . Thus, the distance the light travels inside the plastic is sin dL = , and if 50.0 cm 0.500 m L = = , the time required is ( ) () 8 1.20 0.500 m 0 10 m s sin36.1 ×° 9 sin 3.40 10 s 3.40 ns sin 3.0 L dn L t vc nc ∆= = = = = × = 22.62 (a) At the upper surface of the glass, the critical angle is given by 1 sin air c glass n nn θ == Consider the critical ray PBB : 4 tan 4 c d d tt But, also, 2 22 2 222 1 sin in 1 tan cos sin 1 1 1 cc c n θθ = = 2 s 1 −− Thus, 2 2 1 41 d tn  =   or 2 2 4 1 t n d −= giving 2 4 1 t n d =+ ± ± ± ² ² ± ³ ´ µ ± ² (b) Using the result from Part (a) and solving for d gives 2 4 1 t d n = Thus, if , then 1.52 and 0.600 cm
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This document was uploaded on 10/20/2011.

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