34CHAPTER 15 Thus, if R=×, we must have 31.2710m−()( )10232206.9010m s1.2710msin20.9619550 msyaRvθ−××===273.9 or 218073.9106.1°giving =°−°=. Hence, 37.0 or 53.0°(b) The time of flight for each possible angle of projection is: For 37.0: ( )7010229550
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