34_Chapter 15 HomeworkCH15 Electric Forces and Electric Fields

34_Chapter 15 HomeworkCH15 Electric Forces and Electric Fields

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34 CHAPTER 15 Thus, if R , we must have 3 1.27 10 m () ( ) 10 2 3 2 2 0 6.90 10 m s 1.27 10 m sin2 0.961 9550 ms y aR v θ ×× == = 2 73.9 or 2 180 73.9 106.1° giving −° = . Hence, 37.0 or 53.0° (b) The time of flight for each possible angle of projection is: For 37.0 : ( ) 7 0 10 2 29550
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