Problem 1.5 - 3 = Then p R air T = 0.076 lbm ft 3 = 0.00238...

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Problem 1.5 [Difficulty: 1] Given: Dimensions of a room Find: Mass of air Solution: Basic equation: ρ p R air T = Given or available data p 14.7psi = T 59 460 + () R = R air 53.33 ft lbf lbm R = V1 0 f t 10 × ft 8 × ft = V
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Unformatted text preview: 3 = Then p R air T = 0.076 lbm ft 3 = 0.00238 slug ft 3 = 1.23 kg m 3 = M V = M 61.2 lbm = M 1.90 slug = M 27.8kg =...
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