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Problem 1.18
[Difficulty: 2]
Given:
Basic dimensions F, L, t and T.
Find:
Dimensional representation of quantities below, and typical units in SI and English systems.
Solution:
(a) Power
Power
Energy
Time
Force
Distance
×
Time
=
=
FL
⋅
t
=
Nm
⋅
s
lbf ft
⋅
s
(b) Pressure
Pressure
Force
Area
=
F
L
2
=
N
m
2
lbf
ft
2
(c) Modulus of elasticity
Pressure
Force
Area
=
F
L
2
=
N
m
2
lbf
ft
2
(d) Angular velocity
AngularVelocity
Radians
Time
=
1
t
=
1
s
1
s
(e) Energy
Energy
Force
Distance
×
=
⋅
=
⋅
lbf ft
⋅
(f) Momentum
Momentum
Mass
Velocity
×
=
M
L
t
⋅
=
From Newton's 2nd law
Force
Mass
Acceleration
×
=
so
FM
L
t
2
⋅
=
or
M
Ft
2
⋅
L
=
Hence
Momentum
M
L
t
⋅
=
2
⋅
L
⋅
Lt
⋅
=
⋅
=
Ns
⋅
lbf s
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This note was uploaded on 10/19/2011 for the course EGN 3353C taught by Professor Lear during the Fall '07 term at University of Florida.
 Fall '07
 Lear
 Fluid Mechanics

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