Problem 1.28 - min 1 gal 4 0.946 liter 60 s 1 min = 0.264...

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Problem 1.28 [Difficulty: 1] Given: Data in given units Find: Convert to different units Solution: (a) 1 in 3 min 1 in 3 min 0.0254m 1in 1000 mm 1m × 3 × 1 min 60 s × = 273 mm 3 s = (b) 1 m 3 s 1 m 3 s 1 gal 4 0.000946 × m 3 × 60 s 1 min × = 15850gpm = (c) 1 liter min 1 liter
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Unformatted text preview: min 1 gal 4 0.946 liter 60 s 1 min = 0.264 gpm = (d) 1 SCFM 1 ft 3 min 0.0254 m 1 12 ft 3 60 min 1 hr = 1.70 m 3 hr =...
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This note was uploaded on 10/19/2011 for the course EGN 3353C taught by Professor Lear during the Fall '07 term at University of Florida.

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