Problem 1.29
[Difficulty: 1]
Given:
Density of mercury.
Find:
Specific gravity, volume and weight.
Solution:
Use basic definitions
SG
ρ
ρ
w
=
From Appendix A
ρ
w
1.94
slug
ft
3
⋅
=
so
SG
26.3
1.94
=
SG
13.6
=
v
1
ρ
=
so
v
1
26.3
ft
3
slug
⋅
0.3048m
⋅
1ft
⋅
⎛
⎝
⎞
⎠
3
×
1 slug
⋅
32.2 lbm
⋅
×
1 lbm
⋅
0.4536kg
⋅
×
=
v
7.37
10
5
−
×
m
3
kg
=
γρ
g
⋅
=
Hence on earth
γ
E
26.3
slug
ft
3
⋅
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This note was uploaded on 10/19/2011 for the course EGN 3353C taught by Professor Lear during the Fall '07 term at University of Florida.
 Fall '07
 Lear
 Fluid Mechanics

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