Problem 1.40 - = = = = + = T p T p u RT p RT p T T T u RT...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Problem 1.40 [Difficulty: 2] Given: Air at standard conditions – p = 29.9 in Hg, T = 59°F Uncertainty in p is ± 0.1 in Hg, in T is ± 0.5°F Note that 29.9 in Hg corresponds to 14.7 psia Find: Air density using ideal gas equation of state; Estimate of uncertainty in calculated value. Solution: 2 2 o o 2 ft in 144 R 519 1 lbf ft 53.3 R lb in lbf 7 . 14 × × × = = RT p ρ The uncertainty in density is given by % 0963 . 0 59 460 5 . 0 ; 1 % 334 . 0 9 . 29 1 . 0 ; 1 1 2 2 1 2 2 ± = + ± = = = = ± = ±
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: = = = = + = T p T p u RT p RT p T T T u RT RT RT RT p p u T T u p p u Then ( ) [ ] ( ) [ ] 3 4 2 1 2 2 2 1 2 2 ft lbm 10 66 . 2 % 348 . % 0963 . % 334 . = = + = + = u u u u T p...
View Full Document

Ask a homework question - tutors are online