Problem 2.38

# Problem 2.38 - 2 Check with Appendix A Table A.9 At T 68...

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Problem 2.38 [Difficulty: 2] Given: Sutherland equation with SI units Find: Corresponding equation in BG units Solution: Governing equation: μ bT 1 2 1 S T + = Sutherland equation Assumption: Sutherland equation is valid The given data is b 1.458 10 6 × kg ms K 1 2 = S 110.4 K = Converting constants b 1.458 10 6 × kg ms K 1 2 lbm 0.454 kg × slug 32.2 lbm × 0.3048 m ft × 5K 9R 1 2 × = b 2.27 10 8 × slug ft s R 1 2 = Alternatively b 2.27 10 8 × slug ft s R 1 2 lbf s 2 slug ft × = b 2.27 10 8 × lbf s ft 2 R 1 2 = Also S 110.4 K 9R 5K × = S 198.7 R = and μ bT 1 2 1 S T + = with T in Rankine, μ in lbf s ft

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Unformatted text preview: 2 Check with Appendix A, Table A.9. At T 68 °F = we find T 527.7 R ⋅ = μ 3.79 10 7 − × lbf s ⋅ ft 2 ⋅ = μ 2.27 10 8 − × lbf s ⋅ ft 2 R 1 2 ⋅ 527.7 R ⋅ ( ) 1 2 × 1 198.7 527.7 + = μ 3.79 10 7 − × lbf s ⋅ ft 2 ⋅ = Check! At T 200 °F = we find T 659.7 R ⋅ = μ 4.48 10 7 − × lbf s ⋅ ft 2 ⋅ = μ 2.27 10 8 − × lbf s ⋅ ft 2 R 1 2 ⋅ 659.7 R ⋅ ( ) 1 2 × 1 198.7 659.7 + = μ 4.48 10 7 − × lbf s ⋅ ft 2 ⋅ = Check!...
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Problem 2.38 - 2 Check with Appendix A Table A.9 At T 68...

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