This preview shows page 1. Sign up to view the full content.
Problem 2.41
[Difficulty: 2]
Given:
Velocity distribution between parallel plates
Find:
Force on lower plate
Solution:
Basic equations
F
τ
yx
A
⋅
=
τ
yx
μ
du
dy
⋅
=
du
dy
d
dy
u
max
1
2y
⋅
h
⎛
⎝
⎞
⎠
2
−
⎡
⎢
⎣
⎤
⎥
⎦
⋅
=
u
max
4
h
2
−
⎛
⎜
⎝
⎞
⎠
⋅
2
⋅
y
⋅
=
8u
max
⋅
y
⋅
h
2
−
=
so
τ
yx
8
μ
⋅
u
max
⋅
y
⋅
h
2
−
=
and
F
8A
⋅
μ
⋅
u
max
⋅
y
⋅
h
2
−
=
At the lower surface
y
h
2
−
=
and
h
0.1 mm
⋅
=
A1
m
2
⋅
=
u
max
0.05
m
s
⋅
This is the end of the preview. Sign up
to
access the rest of the document.
This note was uploaded on 10/19/2011 for the course EGN 3353C taught by Professor Lear during the Fall '07 term at University of Florida.
 Fall '07
 Lear
 Fluid Mechanics

Click to edit the document details