Problem 2.43[Difficulty: 2]Given:Velocity profileFind:Plot of velocity profile; shear stress on surfaceSolution:The velocity profile isuρg⋅μhy⋅y22−⎛⎜⎝⎞⎠⋅sinθ()⋅=so the maximum velocity is at y = humaxρg⋅μh22⋅sinθ⋅=Hence we can plotuumax2yh12yh⎛⎝⎞⎠2⋅−⎡⎢⎣⎤⎥⎦⋅=00.250.50.7510.250.50.751u/umaxy/hThis graph can be plotted in ExcelThe given data ish0.1 in⋅=μ2.15103−×lbf s⋅ft2⋅=θ45 deg⋅=Basic equationτyxμdudy⋅=τyxμdudy⋅=μddy⋅ρg⋅μ⋅y22−⎛⎜⎝⎞⎠⋅sinθ⋅
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This note was uploaded on 10/19/2011 for the course EGN 3353C taught by Professor Lear during the Fall '07 term at University of Florida.