Problem 2.47 - L F T c 2 V w = The given data is F T 25 lbf...

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Problem 2.47 [Difficulty: 2] Given: Data on tape mechanism Find: Maximum gap region that can be pulled without breaking tape Solution: Basic equation τ yx μ du dy = and F τ yx A = Here F is the force on each side of the tape; the total force is then F T 2F = 2 τ yx A = c c t y x L F,V The velocity gradient is linear as shown du dy V0 c = V c = The area of contact is Aw L = Combining these results F T 2 μ V c w L = Solving for L L
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Unformatted text preview: L F T c 2 V w = The given data is F T 25 lbf = c 0.012 in = 0.02 slug ft s = V 3 ft s = w 1 in = Hence L 25 lbf 0.012 in 1 ft 12 in 1 2 1 0.02 ft s slug 1 3 s ft 1 1 1 in 12 in 1 ft slug ft s 2 lbf = L 2.5 ft =...
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This note was uploaded on 10/19/2011 for the course EGN 3353C taught by Professor Lear during the Fall '07 term at University of Florida.

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