Problem 2.68 - The data is 2 N (rpm) (Ns/m ) 10 0.121 20...

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The data is N (rpm) µ (N·s/m 2 ) 10 0.121 20 0.139 30 0.153 40 0.159 50 0.172 60 0.172 70 0.183 80 0.185
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The computed data is ω (rad/s) ω/θ (1/s) η (N·s/m 2 x10 3 ) 1.047 120 121 2.094 240 139 3.142 360 153 4.189 480 159 5.236 600 172 6.283 720 172 7.330 840 183 8.378 960 185 From the Trendline analysis k = 0.0449 n - 1 = 0.2068 n = 1.21 The fluid is dilatant The apparent viscosities at 90 and 100 rpm can now be computed
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Problem 2.68 - The data is 2 N (rpm) (Ns/m ) 10 0.121 20...

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