Problem 2.69 - y = 250 Pa we can use the Bingham plastic...

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Problem 2.69 [Difficulty: 4] Given: Data on insulation material Find: Type of material; replacement material Solution: The velocity gradient is du/dy = U/ δ where = 0.001 m Data and τ (Pa) U (m/s) du/dy (s -1 ) computations 50 0.000 0 100 0.000 0 150 0.000 0 163 0.005 5 171 0.01 10 170 0.03 25 202 0.05 50 246 0.1 100 349 0.2 200 444 0.3 300 Hence we have a Bingham plastic, with y = 154 Pa µ p = 0.963 N · s/m 2 At = 450 Pa, based on the linear fit du/dy = 307 s -1 For a fluid with
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Unformatted text preview: y = 250 Pa we can use the Bingham plastic formula to solve for p given , y and du/dy from above p = 0.652 N · s/m 2 Shear Stress vs Shear Strain Linear data fit: τ = 0.9632( du/dy ) + 154.34 R 2 = 0.9977 50 100 150 200 250 300 350 400 450 500 50 100 150 200 250 300 350 du/dy (1/s) (Pa)...
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