Problem 2.70 - at 20 o C 5 0.0116 10 0.0101 Hence, blood is

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Problem 2.70 [Difficulty: 3] Given: Viscometer data Find: Value of k and n in Eq. 2.17 Solution: The data is τ (Pa) du/dy (s -1 ) 0.0457 5 0.119 10 0.241 25 0.375 50 0.634 100 1.06 200 1.46 300 1.78 400 Hence we have k = 0.0162 n = 0.7934 Blood is pseudoplastic (shear thinning) The apparent viscosity from η = k ( du/dy ) n -1 du/dy (s -1 ) (N·s/m 2 ) µ water = 0.001 N · s/m 2
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Unformatted text preview: at 20 o C 5 0.0116 10 0.0101 Hence, blood is "thicker" than water! 25 0.0083 50 0.0072 100 0.0063 200 0.0054 300 0.0050 400 0.0047 Shear Stress vs Shear Strain = 0.0162(du/dy) 0.7934 R 2 = 0.9902 0.01 0.1 1 10 1 10 100 1000 du/dy (1/s) (Pa) Data Power Trendline...
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