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Unformatted text preview: K =  50 o C, it is off scale of Fig. A.3. Instead we need to use formulas as in Appendix A At this altitude the density is (Table A.3) ρ 0.02422 1.225 × kg m 3 ⋅ = ρ 0.0297 kg m 3 = For μ μ b T 1 2 ⋅ 1 S T + = where b 1.458 10 6 − × kg m s ⋅ K 1 2 ⋅ ⋅ = S 110.4 K ⋅ = μ 1.459 10 5 − × kg m s ⋅ = μ 1.459 10 5 − × N s ⋅ m 2 ⋅ = Hence x trans 1.459 10 5 − × kg m s ⋅ ⋅ 500000 × 1 0.0297 × m 3 kg ⋅ 1 2700 × 1 10 3 × hr m ⋅ 3600 s ⋅ 1 hr ⋅ × = x trans 0.327m =...
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This note was uploaded on 10/19/2011 for the course EGN 3353C taught by Professor Lear during the Fall '07 term at University of Florida.
 Fall '07
 Lear
 Fluid Mechanics

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