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Problem 3.8
[Difficulty: 2]
Given:
Properties of a cube floating at an interface
Find:
The pressures difference between the upper and lower surfaces; average cube density
Solution:
The pressure difference is obtained from two applications of Eq. 3.7
p
U
p
0
ρ
SAE10
g
⋅
H
0.1 d
⋅
−
()
⋅
+
=
p
L
p
0
ρ
SAE10
g
⋅
H
⋅
+
ρ
H2O
g
⋅
0.9
⋅
d
⋅
+
=
where
p
U
and
p
L
are the upper and lower pressures,
p
0
is the oil free surface pressure,
H
is the depth of the interface, and
d
is the cube size
Hence the pressure difference is
Δ
pp
L
p
U
−
=
ρ
H2O
g
⋅
0.9
⋅
d
⋅
ρ
SAE10
g
⋅
0.1
⋅
d
⋅
+
=
Δ
p
ρ
H2O
g
⋅
d
⋅
0.9
SG
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This note was uploaded on 10/19/2011 for the course EGN 3353C taught by Professor Lear during the Fall '07 term at University of Florida.
 Fall '07
 Lear
 Fluid Mechanics

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