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Problem 3.8 [Difficulty: 2] Given: Properties of a cube floating at an interface Find: The pressures difference between the upper and lower surfaces; average cube density Solution: The pressure difference is obtained from two applications of Eq. 3.7 p U p 0 ρ SAE10 g ⋅ H 0.1 d ⋅ − () ⋅ + = p L p 0 ρ SAE10 g ⋅ H ⋅ + ρ H2O g ⋅ 0.9 ⋅ d ⋅ + = where p U and p L are the upper and lower pressures, p 0 is the oil free surface pressure, H is the depth of the interface, and d is the cube size Hence the pressure difference is Δ pp L p U − = ρ H2O g ⋅ 0.9 ⋅ d ⋅ ρ SAE10 g ⋅ 0.1 ⋅ d ⋅ + = Δ p ρ H2O g ⋅ d ⋅ 0.9 SG
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This note was uploaded on 10/19/2011 for the course EGN 3353C taught by Professor Lear during the Fall '07 term at University of Florida.
- Fall '07
- Fluid Mechanics