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Problem 3.11

# Problem 3.11 - Problem 3.11[Difficulty 2 Given Properties...

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Problem 3.11 [Difficulty: 2] Given: Properties of a cube suspended by a wire in a fluid Find: The fluid specific gravity; the gage pressures on the upper and lower surfaces Solution: From a free body analysis of the cube: Σ F0 = Tp L p U () d 2 + Mg = where M and d are the cube mass and size and p L and p U are the pressures on the lower and upper surfaces For each pressure we can use Eq. 3.7 pp 0 ρ g h + = Hence p L p U p 0 ρ g Hd + + p 0 ρ g H + = ρ g d = SG ρ H2O d = where H is the depth of the upper surface Hence the force balance gives SG T ρ H2O g d 3 = SG 2 slug 32.2 × ft s 2 lbf s 2 slug ft × 50.7 lbf 1.94 slug ft 3 32.2 × ft s 2 lbf s 2 slug ft × 0.5 ft 3 × = SG 1.75 = From Table A.1, the fluid is Meriam blue. The individual pressures are computed from Eq 3.7 0 ρ g h + = or p g ρ g h = SG ρ H2O h = For the upper surface p g 1.754 1.94 × slug ft 3 32.2 × ft s 2 2 3 × ft
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